Something I never seem to read about is how many more lithium batteries a motor needs to use to achieve higher range then a lead acid battery.

Let's just make up some number here...

Motor = 48-72 VDC 10hp/40hp peak single-shaft 62lbs.

Weight = 200lb minus batteries

Range = 70 mile safe / 100 mile max(drained batteries)

Now then.. Using Optima Blue/Yellow Top 12v 50ah batteries. It would take 6 of them in series to power the vehicle. Each at 45lbs adding 270lbs to the bike. This should get the bike close half the range we are looking for.

Time to jumble with lithium battery. Using a Lithium D battery 3.6v 1ah(guessing it's ah). It will take 20 of these in series to reach 72v. Each at 3oz x 20 = 60oz OR 3.75lbs. Obviously, these 20 batteries could turn the motor. However, they would be able to handle pushing that kind of weight for more then a block.

Here is the actual forum question I am asking..

Keeping in mind that 50% of my numbers are completely made up. How many lithium batteries would it take just to equal the 6 lead acid batteries?

300?

Also, would that mean running 15 packs of 20 lithium batteries in parallel?

I didn't get to goto MIT like Lennon(emoto) did.

So I just work it out as a go.

Thanks