Originally Posted by elevatorguy
From the little I have read, the air source is in the 4500 to 5000 psi range, I think that you would have to jump a heavy car to even approach that range.
Or simply reduce the diameter of the piston in each pump. But, as with any other mechanical energy conversion device, it's a trade-off. The higher the PSI, the lower the volume of air added to the tank.
For a 3000 pound car, each wheel would have (on average) 750 pounds of static weight. (The dynamic weight would be significantly greater, but I have no way of estimating dynamic weight at the moment.) So to achieve 5000 PSI, the pump piston would have to have an area of 0.15 square inches, or a diameter of 0.437 inches.
( 750 lb / 5000 lb/sqin = 0.15 sqin )
( 2 * SQROOT(0.15 sqin / Pi) = 0.437 in diameter )
If the average travel is 3 inches per bounce (purely a guess), then the volume of air (at 1 atm) added per bounce is 0.45 cubic inches. Multiply that by four (since this is for each wheel), and you get 1.8 cubic inches of air (at 1 atm) per bounce.
I don't know the CA engine efficiencies, but this doesn't sound insignificant to me. I think it would be worth exploring.
Does anyone have an estimate on how much a car "bounces" per mile?