I've got two strings of ThunderSky cells, 35 cells each, one string of
200Ah cells and one string of 90Ah cells, all with shunt regulators on
them. The two strings are connected to each other through circuit
breakers on both the positive and negative terminals. I want to test
out charging the two strings in parallel, so I need to connect them
together. The 200Ah string is at currently 142V and the 90Ah string is
at 136V. I think I should be okay just flipping on the circuit
breakers, but I want to verify I'm thinking about it correctly. Using
an internal resistance of .005 ohms for the 200Ah cells and .015 Ohm
for the 90Ah cells (I think resistances both are actually higher, but I
want to be conservative in my estimates), then the current through the
cells when the circuit breakers are turned on and the cells start to
equalize would be I = V/R:
(142 - 136) / ((.005 * 35) + .(015 * 35)) = 9A
Have I thought about that correctly?
Thanks.
Bill Dennis
_______________________________________________
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200Ah cells and one string of 90Ah cells, all with shunt regulators on
them. The two strings are connected to each other through circuit
breakers on both the positive and negative terminals. I want to test
out charging the two strings in parallel, so I need to connect them
together. The 200Ah string is at currently 142V and the 90Ah string is
at 136V. I think I should be okay just flipping on the circuit
breakers, but I want to verify I'm thinking about it correctly. Using
an internal resistance of .005 ohms for the 200Ah cells and .015 Ohm
for the 90Ah cells (I think resistances both are actually higher, but I
want to be conservative in my estimates), then the current through the
cells when the circuit breakers are turned on and the cells start to
equalize would be I = V/R:
(142 - 136) / ((.005 * 35) + .(015 * 35)) = 9A
Have I thought about that correctly?
Thanks.
Bill Dennis
_______________________________________________
For subscription options, see
http://lists.sjsu.edu/mailman/listinfo/ev