--- Roland Wiench <

[email protected]> wrote:

> If you have a Emeter, than you can use the watts per

> mile instead of the AH.

> Of course this will be the average amount of battery

> amperes times battery

> voltages.

>

> Or if you have a AC input volt-amp meter and

> calculated the volts x amps =

My conversion is a DC system?.

http://www.austinev.org/evalbum/736.

This is how I came up with the watts: 156v x 90amp

@60mph.= 14040 wh./ 60mph=234wh/mi. is that correct ?

> watts for a constant current charger and average out

> the voltage curve or

> better yet, use a AC watt meter to give you how many

> kilowatt hr it takes to

> charge the batteries for a given number of miles.

>

> Or just take the average battery amperes times the

> average voltages for a

> ball park estimate for the wattages.

>

> Now lets say you use about 10k watts to go 50 miles,

> then if you paying 11.5

> cents per kilowatt, then the 50 miles will cost you

> about $0.115 x 10 =

> $1.15

>

> If gasoline is $3.45 a gallon, then $3.45/$1.15 = 3

>

> So you can go 3 times the distance with the electric

> with $3.45 or would be

> equivalent to 3 x 50 miles = 150 miles per gallon

> equiavlent or MPGE

>

> The formula now becomes:

>

> MPGE = ((cost of gal of gas)/(kw use x cost per

> kw))x miles travel

Thanks, I can follow this "mpge"

What I want to do is just find out my mpge for

several speeds, say 25mph, 35 and 60mph. Just to get

an idea of my efficiency.

Thanks again,

Jeff

>

> Roland

>

> ----- Original Message -----

> From: "Jeff Mccabe" <

[email protected]>

> To: "ev-list" <

[email protected]>

> Sent: Wednesday, August 01, 2007 3:26 PM

> Subject: MPG Equivalent ?

>

>

> > I don't know the formula for figuring my mpg

> > equivalent for my conversion.

> > My nominal pack voltage is 156volts and I'm

> drawing

> > right around 90amps on level ground at 60mph(234

> > wh/mi). Electricity costs me 11.5 cents per

> kilowatt.

> > If you could share the formula so I can save it

> for

> > future testing this would really help.

> > Thanks,

> > Jeff McCabe

> >

> >

>

>