Yes, any controller that uses internal contactors will control its own precharge. In the case of the PulsaR it likely runs on Unicorn blood to make pigs fly as well.
This may help. http://liionbms.com/php/precharge.phpSo I guess that the output of this formula would be the resistance and from there you could calculate the power dissipation at full load. But then the next question arises: the time to pre-charge is quite short. If you get 1000W maximum input current, do your really need a 1000w resistor or would it be overkill ? (as it won't be a continuous current).
Neuweiler, I gave you the formula but you didn't recognize it in text. "the R C Time constant Formula. That is Capacitance of the input capacitor bank totalized in Farads multiplied by the resistance in ohms is the time in seconds to reach 63.7% of the full applied voltage across the capacitors. We want the full voltage so the time needed is at least three times that Time calculated up to five times that Time calculated." In algebraic form that is RC=Tc or resistance in Ohms times the Sum of the input capacitors (Because there are usually several you just add them together.) equals the "Time Constant for that amount of resistance and capacitance. and the "TC" in seconds is the time to charge the capacitors to 63.7% of the applied voltage then in the same number of additional seconds it charges up 63.7% of the remaining voltage and in five times the charge reaches 99.5% so we consider the capacitors fully charged. As a rule of "Thumb" we usually use about 470 to 750 ohms. Also the actual average dissipated power is only a fraction of a watt however we use a physically substantially larger resister for physical strength and vibration resistance from driving on cobblestone roads and such. Typical is a five watt resistor supported with a nylon clamp and bolted to a strong surface. For the same reason I usually connect it up with (American Wire Gauge) # AWG-12 stranded wire. The voltage does not affect the resistance for a particular time ... nor does the amperage capability of the system as that current does not pass thru the resistor. we just allow the capacitors to charge up slowly for five to ten seconds to minimize the surge of charging up discharged capacitors when first applying the full battery pack voltage. (It saves the relay some wear and tear upon switching on...) I'm here if you have more questions.EC nut, thanks a lot! Do you happen to have the formula at hand?
To be honest, the light bulb approach would be a bit too geeky for my taste. I'd prefer a resistor in a cool looking case.
So I guess that the output of this formula would be the resistance and from there you could calculate the power dissipation at full load. But then the next question arises: the time to pre-charge is quite short. If you get 1000W maximum input current, do your really need a 1000w resistor or would it be overkill ? (as it won't be a continuous current).
Davide, only one problem, the current does not flow into the positive terminal of the relay, the Electrons do. but current flows the other direction (Especially for those of us educated in "Classic Electric Engineering" I could treat you to the 30 minute lecture on current flow but.....and the fee is $50 and you won't have to feel ignorant again. 8^)This may help. http://liionbms.com/php/precharge.php
I assume you refer to Davide's quote here:Davide, only one problem, the current does not flow into the positive terminal of the relay, the Electrons do. but current flows the other direction (Especially for those of us educated in "Classic Electric Engineering" I could treat you to the 30 minute lecture on current flow but.....and the fee is $50 and you won't have to feel ignorant again. 8^)
He is correct and consistent with EE convention with regards to current flow. You should follow his advice if you wish for your contactor to work properly.In that case, the contacts of the contactors are polarized (one terminal is labeled '+'); connect the contactor so that normally (that is, while discharging) the current flows into the '+' terminal.
Davide stated it correctly. Why do you choose to insult him (and me) and confuse the issue for the reader?Major, and Davide, The discrepancy comes from engineers speaking to technicians.
As Engineers tend to use, Conventional Current Flow (From Positive to Negative).
Alternatively most Technicians use Electron Current Flow (From Negative to Positive) thus the simple statement, "the current flows into the terminal marked (+)" is inadequate to describe the direction of current flow. The relay is not a source, it is marked similarly to a "Load" and the (+) of the pack is connected to the (+) of the contactor.
It is simple ,wire the recharge resistor Across the Main terminals of the main contactor, there is a great video on you tube ,look up DIY pre charge resistor ,he explains it in layman's terms, installed on go cart!Fair enough. Could someone please explain in detail how you would wire the pre-charge resistor? is it just another power cable going to the controller with a resistor connected in-line?